3m^2+13m+12=0

Solution for 3m^2+13m+12=0 equation:

3m^2+13m+12=0

a = 3; b = 13; c = +12;
Δ = b2-4ac
Δ = 132-4·3·12
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-5}{2*3}=\frac{-18}{6}
=-3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+5}{2*3}=\frac{-8}{6}
=-1+1/3
$